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Von Braun
Thursday, November 25th, 2004, 11:07 PM
The four outer-most points of the Swastika lie on an inner circle. The boundary between the red region and the white region is an outer circle. What is the ratio of the radius of the inner circle to the radius of the outer circle?

I really doubt that Hitler would have left an arbitrary amount of clearance between the black and the red. Therefore, I conclude that something must have went into his choice.

From eyeballing the flag, I estimate that the ratio is ~ 0.95.

Patria
Friday, November 26th, 2004, 09:53 AM
Is there hidden mathematical significance in the flag that Hitler designed?The swastika embodies the mathematical sequence 2, 4, 8:

- Two (2) equal-length lines are crossed,
- forming four (4) equal-length arms relative to the swastika’s center point,
- and each of these four arms is bent at a right angle at its halfway point, giving a total of eight (8) equal lengths.

It is perhaps worth noting that the mathematical sequence of 2, 4, 8, is equivalent to the mathematical sequence of 21, 22, 23—three successive powers of 2, which can be seen as suggestive of the bits used in binary computing.

Understanding the Flag of National Socialist Germany (http://www.johmann.net/commentary/german-flag.html)

Von Braun
Saturday, December 4th, 2004, 07:18 AM
The swastika embodies the mathematical sequence 2, 4, 8:

Thule, you made me think of something. The next power of 2 would be 16. Assuming Hitler wanted to continue this sequence by leaving an amount of clearance equal to 1/16 of the radius of the larger circle, that would mean the ratio would be 15/16 = 0.9375 which is very close to the 0.95 that I estimated.

It is perfect: four powers of two: 2, 4, 8, and 16. This makes more sense than having three powers of two.

I shall measure it precisely when I have the chance.